Fix the program 2

Similarly to 1.5.2-1 this program takes an integer and counts it towards 0. However, it counts at a factor of 2.

This makes odd numbers not reach 0 properly, which leads to an unintended infinite loop. Fix the program by making it reach 0 on the last count.

#include <iostream>

int main()
{
	std::cout << "Input an integer you want to count towards 0.\n";
	int input;
	std::cin >> input;

	while (input != 0)
	{
		if (input > 0)
			input -= 2;
		else
			input += 2;

		std::cout << input << "\n";
	}
}

Example

4

2
0

---

5

3
1
-1
1
-1
1
-1
1
-1
...

Answer

#include <iostream>

int main()
{
	std::cout << "Input an integer you want to count towards 0.\n";
	int input;
	std::cin >> input;

	while (input != 0)
	{
		// If the current value is higher than 2 we always want to decrement it by 2
		if (input >= 2)
			input -= 2;
		// The same thing goes if it's smaller than -2
		else if (input <= -2)
			input += 2;
		// At this point the input is either 1 or -1. Either way the next value `input` should have is 0.
		else
			input = 0;

		std::cout << input << "\n";
	}
}

By adding an if chain like this we make sure that the program functions like normal (counting with a factor of 2) untill the number is between 2 and -2, at which point we set it to 0, completing the loop.